High School

Which calculation and answer show how to convert [tex]\frac{5}{16}[/tex] to a decimal?

A.
[tex]
\begin{array}{r}
3.125 \\
1 6 \longdiv { 5 . 0 0 0 0 } \\
-\frac{48}{20} \\
20 \\
-16 \\
40 \\
-\frac{32}{40} \\
-32 \\
8
\end{array}
[/tex]

B.
[tex]
\begin{array}{r}
16 \\
\times \quad 5 \\
\hline
80
\end{array}
[/tex]

C.
[tex]
\begin{array}{r}
0.3125 \\
1 6 \longdiv { 5 0 0 0 0 } \\
-48 \\
\hline
20 \\
-16 \\
40 \\
-32 \\
\hline
80 \\
-80 \\
0
\end{array}
[/tex]

D.
[tex]
\begin{array}{r}
32 \\
5 \longdiv { 1 6 0 } \\
-15 \\
\hline
10 \\
-10 \\
0
\end{array}
[/tex]

Answer :

To convert the fraction [tex]\(\frac{5}{16}\)[/tex] to a decimal, you need to perform long division, dividing 5 by 16. Let's go through the steps:

1. Set up the division: Place 5 inside the division bracket and 16 outside.

2. Perform the division:

- Since 16 doesn't go into 5, you need to add a decimal point and proceed by adding zeros to 5, making it 5.0000.

- Determine how many times 16 fits into 50. It fits 3 times (since 16 x 3 = 48).

- Write 3 above the division line, right after the decimal point. Subtract 48 from 50, which leaves a remainder of 2.

3. Bring down the next zero, making it 20:

- Determine how many times 16 fits into 20. It fits 1 time (since 16 x 1 = 16).

- Write 1 above the division line. Subtract 16 from 20, which leaves a remainder of 4.

4. Bring down the next zero, making it 40:

- Determine how many times 16 fits into 40. It fits 2 times (since 16 x 2 = 32).

- Write 2 above the division line. Subtract 32 from 40, which leaves a remainder of 8.

5. Bring down the last zero, making it 80:

- Determine how many times 16 fits into 80. It fits 5 times (since 16 x 5 = 80).

- Write 5 above the division line. Subtract 80 from 80, which leaves a remainder of 0.

So, the division shows that [tex]\(\frac{5}{16} = 0.3125\)[/tex].

This calculation matches the calculation shown in choice C:

[tex]\[
\begin{array}{r}
0.3125 \\
1 6 \longdiv { 5 0 0 0 0 } \\
-48 \\
\hline 20 \\
-16 \\
40 \\
-32 \\
\hline 80 \\
-\frac{80}{0}
\end{array}
\][/tex]

Therefore, the correct answer is choice C.