Answer :
Final answer:
To make a 1.5M solution of propanol in water, you would dissolve 90.0 grams of propanol to make a 0.998L (or 998 mL) solution.
Explanation:
To make a 1.5M solution of propanol in water, you need to calculate the volume of solution that would be made by dissolving 90.0 grams of propanol. The molecular weight of propanol is 60.10 g/mol. First, calculate the number of moles of propanol:
- 90.0 g / 60.10 g/mol = 1.497 moles of propanol
Since the concentration is given in Molarity (M), which is moles of solute per liter of solution, the volume of solution can be calculated using the formula:
- Volume (L) = Moles / Concentration (M)
Plugging in the values:
- Volume = 1.497 mol / 1.5 M = 0.998 L
Therefore, the volume of solution that would be made by dissolving 90.0 grams of propanol is 0.998 L (or 998 mL).
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Final answer:
Approximately 1.0L of a 1.5M solution can be made from dissolving 90.0 grams of propanol, given that its molar mass is 60.10 g/mol.
Explanation:
To determine what volume of solution would be made by dissolving 90.0 grams of propanol to create a 1.5M solution, we first need to calculate the number of moles of propanol using its molar mass. The molar mass of propanol (CH₃CH₂CH₂OH) is 60.10 g/mol. The number of moles of propanol in 90.0 grams is therefore:
moles = mass / molar mass = 90.0 g / 60.10 g/mol = 1.498 moles (rounded to three decimal places)
Next, we divide the number of moles of propanol by the desired molarity to find the volume in liters:
volume = moles / molarity = 1.498 moles / 1.5M = 0.999 L
Therefore, the volume of solution that can be prepared from 90.0 grams of propanol to achieve a molarity of 1.5M is approximately 1.0L.
