Answer :
To find the mass of oxygen required to convert 4.00 g of sulfur into sulfur trioxide (SO3), we can use the law of conservation of mass.
In the given reaction, 4.00 g of sulfur combines with 4.00 g of oxygen to form 8.00 g of sulfur dioxide (SO2). So, to find the mass of oxygen required to convert 4.00 g of sulfur into sulfur trioxide (SO3), we need to determine the difference in mass between SO3 and SO2. Sulfur trioxide (SO3) has a molar mass of 80.06 g/mol, while sulfur dioxide (SO2) has a molar mass of 64.07 g/mol.
Therefore, to convert 4.00 g of sulfur into SO3, we would need 15.99 g of oxygen. To calculate the mass of oxygen required to convert 4.00 g of sulfur into sulfur trioxide (SO3), we can use the law of conservation of mass. This law states that the mass of the reactants must be equal to the mass of the products in a chemical reaction. In the given reaction, 4.00 g of sulfur combines with 4.00 g of oxygen to form 8.00 g of sulfur dioxide (SO2). To find the mass of oxygen required to form SO3, we need to determine the difference in mass between SO3 and SO2. Therefore, to convert 4.00 g of sulfur into SO3, we would need 15.99 g of oxygen.
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The mass of oxygen required to convert 4.00 g of sulfur into sulfur trioxide (SO3) is approximately 1.9976 grams.
To find the mass of oxygen required to convert 4.00 g of sulfur into sulfur trioxide (SO3), we can use the concept of stoichiometry.
First, let's calculate the molar mass of sulfur and oxygen. Sulfur has a molar mass of 32.07 g/mol, and oxygen has a molar mass of 16.00 g/mol.
Next, we need to find the moles of sulfur and oxygen in the given 4.00 g of sulfur. To do this, we divide the mass of sulfur by its molar mass:
Moles of sulfur = Mass of sulfur / Molar mass of sulfur
Moles of sulfur = 4.00 g / 32.07 g/mol
Moles of sulfur = 0.1248 mol (approximately)
Since the reaction is balanced, we know that the ratio of moles of sulfur to moles of oxygen is 1:1. Therefore, we need the same number of moles of oxygen as sulfur.
Now, we can calculate the mass of oxygen needed to react with 0.1248 mol of sulfur. To do this, we multiply the moles of sulfur by the molar mass of oxygen:
Mass of oxygen = Moles of sulfur × Molar mass of oxygen
Mass of oxygen = 0.1248 mol × 16.00 g/mol
Mass of oxygen = 1.9976 g (approximately)
So, approximately 1.9976 grams of oxygen would be required to convert 4.00 grams of sulfur into sulfur trioxide (SO3).
Therefore, the mass of oxygen required to convert 4.00 g of sulfur into sulfur trioxide (SO3) is approximately 1.9976 grams.
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