Answer :
When 2. 00 kJ of energy is transferred as heat to nitrogen in a cylinder fitted with a piston with an external pressure of 2. 00 atm, the nitrogen gas expands from 2. 00 to 5. 00 l. The change in internal energy of this system will be ΔU= 1.3922 KJ
Work done on the system taken as negative and work done by the system taken as positive.
Work done by the gas W
Work = P ΔV
W= P ( V₂- V₁)
W= 2 ( 5 - 2)
W= 6 atm L or 0.6078 KJ
using first law of thermodynamics
Q= W + ΔU
2 = 0.6078 + ΔU
ΔU= 1.3922 KJ
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