College

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ What would be the height if your rocket were in the air for 5.2 seconds?

Use the formula:
[tex]\[ h = \frac{1}{2} a t^2 + v_0 t + h_0 \][/tex]

A. 30.6
B. 34.9
C. 39.1
D. None of the above

Answer :

Let's determine the height of the rocket after 5.2 seconds using the equation:

[tex]\[ h = \frac{1}{2} a t^2 + v_0 t + h_0 \][/tex]

Here are the given values:

- [tex]\( a \)[/tex] (acceleration) = 0, meaning there are no external forces acting on the rocket vertically.
- [tex]\( t \)[/tex] (time) = 5.2 seconds
- [tex]\( v_0 \)[/tex] (initial velocity) = 0, implying the rocket started from rest.
- [tex]\( h_0 \)[/tex] (initial height) = 0, indicating the rocket launched from ground level.

Substitute these values into the equation:

[tex]\[ h = \frac{1}{2} \times 0 \times (5.2)^2 + 0 \times 5.2 + 0 \][/tex]

Simplifying it:

[tex]\[ h = 0 + 0 + 0 \][/tex]

[tex]\[ h = 0 \][/tex]

So, the height of the rocket after 5.2 seconds is 0.

Among the options provided (30.6, 34.9, 39.1, None), the correct option is None.