What will this program display?

```cpp
int main() {
throw 42;
cout << "honeybee\n";
}
```

A. honeybee

B. 42

C. an error message

D. 42 honeybee

E. 42 honeybee an error message

F. an error message honeybee

The program throws an exception with 'throw 42' and contains no exception handling, which leads to program termination with an error message before 'honeybee' is printed. Therefore, only an error message will be displayed.

Explanation:

The program in question is a C++ program that, when executed, attempts to perform an operation that involves throwing an exception with the value 42. The line with throw 42 immediately causes the program to throw an exception, and because there is no exception handling mechanism present (such as a try-catch block), the program will terminate and will not execute the cout statement following the throw. Therefore, the message 'honeybee' will not be displayed. Since the exception is not handled, usually an error message is generated by the runtime system, indicating that an unhandled exception has occurred.

Based on this information, the correct answer is:

What will this program display?```cppint main() { throw 42; cout << "honeybee\n";}```A. honeybeeB. 42C. an error messageD. 42 honeybeeE. 42 honeybee an error messageF. an error message honeybee

Answer :

Final answer:

Explanation:

C. an error message

Other Questions

What will this program display?

```cpp
int main() {
throw 42;
cout << "honeybee\n";
}
```

A. honeybee

B. 42

C. an error message

D. 42 honeybee

E. 42 honeybee an error message

F. an error message honeybee