What will be displayed by the following code?

```python
# Start of Code
def f(value, values):
V = 1
values[0] = 44
# End of function

t = 3
v = [1, 2, 3]
f(t, v)
print(t, v[0])
# End of code
```

A. 1 44
B. 11
C. 3 44
D. 31

Answer :

The provided Python code modifies a list and prints values; the output will be '3 44' due to the list being modified by reference in the function. So, correct the option is c. 3 44.

Here's a breakdown of what happens:

Function Definition (f):

The function f takes two arguments: value and values.

Inside the function, it assigns the value 1 to a variable V (not used later).

Importantly, it modifies the first element of the list passed as values by assigning it 44. This change happens because Python functions receive mutable objects (like lists) by reference.

Main Code:

t is assigned the value 3.

v is a list containing [1, 2, 3].

Function Call:

f(t, v) calls the function f with arguments t (3) and v (the list).

Inside the function, v[0] (the first element of the list) is changed to 44. Since lists are mutable, this modification affects the original v list.

Printing:

print(t, v[0]) prints the value of t (which remains 3) and the current value of v[0] (which is now 44).

So, correct the option is c. 3 44.