Answer :
To find out what volume 6.00 moles of ammonia gas (NH₃) will occupy at STP (Standard Temperature and Pressure), we follow these steps:
1. Understand STP: At Standard Temperature and Pressure, which is 0°C (273.15 K) and 1 atm pressure, one mole of any ideal gas occupies 22.4 liters.
2. Moles of Ammonia: We know that we have 6.00 moles of ammonia gas.
3. Calculate the Volume: To find the total volume occupied by 6.00 moles of ammonia at STP, we multiply the number of moles by the volume that one mole occupies:
[tex]\[
\text{Volume of Ammonia} = \text{Moles of Ammonia} \times \text{Volume per mole at STP}
\][/tex]
[tex]\[
\text{Volume of Ammonia} = 6.00 \, \text{moles} \times 22.4 \, \text{liters/mole}
\][/tex]
4. Final Result: By performing the multiplication, we find that the volume occupied by 6.00 moles of ammonia gas at STP is approximately 134.4 liters.
Therefore, 6.00 moles of ammonia gas will occupy about 134.4 liters at STP.
1. Understand STP: At Standard Temperature and Pressure, which is 0°C (273.15 K) and 1 atm pressure, one mole of any ideal gas occupies 22.4 liters.
2. Moles of Ammonia: We know that we have 6.00 moles of ammonia gas.
3. Calculate the Volume: To find the total volume occupied by 6.00 moles of ammonia at STP, we multiply the number of moles by the volume that one mole occupies:
[tex]\[
\text{Volume of Ammonia} = \text{Moles of Ammonia} \times \text{Volume per mole at STP}
\][/tex]
[tex]\[
\text{Volume of Ammonia} = 6.00 \, \text{moles} \times 22.4 \, \text{liters/mole}
\][/tex]
4. Final Result: By performing the multiplication, we find that the volume occupied by 6.00 moles of ammonia gas at STP is approximately 134.4 liters.
Therefore, 6.00 moles of ammonia gas will occupy about 134.4 liters at STP.
