Answer :
To calculate the volume of helium needed to lift a load plus the weight of the balloon, we can use the principle of buoyancy. By equating the buoyant force with the total weight, we determine the volume of helium.
According to Archimedes' principle, the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. In this case, the balloon filled with helium displaces air and experiences an upward buoyant force equal to the weight of the displaced air.
To lift the load and its own weight, the buoyant force must be equal to the total weight. The total weight is the sum of the load weight and the balloon weight.
Using the densities of air (1.29 kg/m^3) and helium (0.179 kg/m^3), along with the acceleration due to gravity (9.8 m/s^2), we can set up the equation:(Density of air * Volume of balloon * g) + (Density of helium * Volume of balloon * g) = Total weight Solving for the volume of the balloon (V), we rearrange the equation:V = (Total weight) / ((Density of air - Density of helium) * g).
By substituting the given values, we find that the volume of helium needed to lift the load and the balloon is approximately 179.1 m^3. This represents the required volume of helium to achieve the necessary buoyant force and lift the specified weight.
To learn more about density, click here: brainly.com/question/28929608
#SPJ11
