Answer :
The mass of NaCl required to make 98.099999999999994 mL of a 0.405M solution of NaCl is c. 2.3218504199999996g.
To find the mass of NaCl needed, we start with the formula for molarity (M), which is defined as moles of solute per liter of solution. The given molarity is 0.405M, and the volume of the solution is 98.099999999999994 mL, which is equivalent to 0.0981 liters (since 1 mL = 0.001 liters).
First, calculate the moles of NaCl required:
\[ \text{Moles of NaCl} = \text{Molarity} \times \text{Volume (in liters)} \]
\[ \text{Moles of NaCl} = 0.405 \times 0.0981 \]
\[ \text{Moles of NaCl} = 0.0397305 \text{ moles} \]
Next, we need to convert moles of NaCl to grams. The molar mass of NaCl (sodium chloride) is approximately 58.44 g/mol.
\[ \text{Mass of NaCl} = \text{Moles of NaCl} \times \text{Molar mass of NaCl} \]
\[ \text{Mass of NaCl} = 0.0397305 \times 58.44 \]
\[ \text{Mass of NaCl} = 2.3218504199999996 \text{ grams} \]
Thus, the mass of NaCl required is 2.3218504199999996 grams, which corresponds to option c. This calculation ensures that the concentration and volume are correctly accounted for to prepare the desired solution.
The correct answer is option c) 2.3218504199999996 g is mass of NaCl.
To solve this problem, we need to find the mass of NaCl required to make 98.099999999999994 mL of a 0.405 M solution of NaCl.
The formula to calculate the mass of a solute required to make a solution of a given volume and concentration is:
m = V × c × M
Where:
- m is the mass of the solute (in this case, NaCl)
- V is the volume of the solution
- c is the concentration of the solution
- M is the molar mass of the solute
Given information:
- Volume of the solution (V) = 98.099999999999994 mL
- Concentration of the solution (c) = 0.405 M
- Molar mass of NaCl (M) = 58.44 g/mol
Substituting the values in the formula:
m = V × c × M
m = 98.099999999999994 mL × 0.405 M × (58.44 g/mol)
m = 2.3218504199999996 g
