High School

What is the velocity (in m/s) of a 925 kg car, initially moving at 29.5 m/s, just after it hits a 145 kg deer, initially running at 12.5 m/s in the same direction? Assume the deer remains on the car. (Enter the magnitude.)

Answer :

The velocity after the collision is 27.19 m/s

What is the law of conservation of momentum?

For a collision between Object 1 and Object 2 in an isolated system, the total momentum of the two objects before collision equals the total momentum of the two objects after collision. That is, the momentum lost from object 1 is equal to the momentum gained from object 2 (a constant or unchanging value). It can be stated by following equation:

Pₙ = mₙvₙ

mₙvₙ = m₁v₁ + m₂v₂

Where, Pₙ = final momentum

mₙ = total mass of the system

vₙ = final velocity of the system

For the given case,

Since, mₙvₙ = m₁v₁ + m₂v₂

(m₁ + m₂)vₙ = m₁v₁ + m₂v₂

(925 + 145)vₙ = (925 × 29.5) + (145 × 12.5)

1070 vₙ = 27287.5 + 1812.5

1070 vₙ = 29100

vₙ = [tex]\frac{29100}{1070}[/tex]

vₙ = 27.19 m/s

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