Middle School

What is the specific heat of a substance that requires 99,100 J of thermal energy to heat 3.47 kg of this substance from 15°C to 41°C?

Answer :

The specific heat of a substance that requires 99,100 Joule will be 1,098.43 J / (kg-K).

What is the specific heat?

Heat capacity is analogous to an object's 'heat content,' or barrier properties to temperature change. Water has a very large specific heat; it takes a lot of time to dissipate heat and another long time to gain heat. As a result, it is extremely resistant to temperature changes.

The specific heat is given as,

Q = mC ΔT

Where Q is the heat required or loss, m is the mass, C is the specific heat, and ΔT is the change in temperature.

The specific heat is given as,

99,100 = 3.47 x C x (41 - 15)

99,100 = 3.47 x C x 26

99,100 = 90.22C

C = 1,098.43 J / (kg-K)

A material that needs 99,100 Joules will have a specific heat of 1,098.43 J/kg (kg-K).

More about the specific heat link is given below.

https://brainly.com/question/11297584

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