Answer :
The correct relationship between the 4s in the number 4498 is that they are both in the units place, and the second 4 is in the tens place.
To understand the relationship between the digits in the number 4498, let's break it down by place value:
- The first 4 (from the right) is in the units place, which is the [tex]10^0[/tex] place.
- The second 4 (to the left of the first 4) is in the tens place, which is the [tex]10^1[/tex] place.
- The next digit, 9, is in the hundreds place, which is the [tex]10^2[/tex] place.
- The last digit, 8, is in the thousands place, which is the [tex]10^3[/tex] place.
So, the number 4498 can be expanded as:
[tex]4498 = (4 * 10^3) + (4 * 10^2) + (9 * 10^1) + (8 * 10^0)[/tex]
In this expansion, we can see that the first 4 is multiplied by 10^0 (which is 1), and the second 4 is multiplied by [tex]10^1[/tex] (which is 10). Therefore, the second 4 contributes ten times more to the value of the number than the first 4.
To illustrate this further, let's calculate the value contributed by each digit:
- The first 4 contributes [tex]4 * 10^0 = 4[/tex]
- The second 4 contributes [tex]4 * 10^1 = 40[/tex]
- The 9 contributes [tex]9 * 10^2 = 900[/tex]
- The 8 contributes [tex]8 * 10^3 = 8000[/tex]
Adding these up gives us the total value of the number:
4498 = 4 + 40 + 900 + 8000
4498 = 8944
Thus, the relationship between the 4s in the number 4498 is that the first 4 is in the units place and the second 4 is in the tens place, contributing ten times more to the value of the number.
