College

What is the quotient of the following division problem?

[tex]\[ 16 \longdiv {1516} \][/tex]

A. 94 r 13
B. 96 r 11
C. 94 r 12
D. 93 r 11

Answer :

Sure! Let's break down the division problem [tex]\(1516 \div 16\)[/tex] step-by-step to find the quotient and remainder.

1. Set up the division: We want to divide 1516 by 16.

2. Divide the first part of the number:
- 16 goes into 151 a certain number of times.
- 16 9 = 144, and 16 10 = 160. Since 160 is too big, 16 fits into 151 a total of 9 times.
- So, we write 9 as the first digit of our quotient.
- Subtract 144 from 151 to get the remainder: [tex]\(151 - 144 = 7\)[/tex].

3. Bring down the next digit:
- Next, bring down the 6 from 1516, making it 76 now.
- We need to determine how many times 16 fits into 76.
- 16 4 = 64, and 16 5 = 80. Since 80 is too big, 16 fits into 76 a total of 4 times.
- So, we write 4 as the next digit of our quotient.
- Subtract 64 from 76 to get the remainder: [tex]\(76 - 64 = 12\)[/tex].

4. Combine the results:
- The quotient is the digits we've written: 94.
- The remainder is 12.

So, the quotient of the division problem [tex]\(1516 \div 16\)[/tex] is [tex]\(94\)[/tex] with a remainder of [tex]\(12\)[/tex].

The correct answer is:
C. 94 r 12