Answer :
To find the product of
[tex]$$
(-2x - 9y^2)(-4x - 3),
$$[/tex]
we multiply each term in the first parenthesis by each term in the second parenthesis.
1. Multiply the first terms:
[tex]$$
(-2x) \cdot (-4x) = 8x^2
$$[/tex]
2. Multiply the outer terms:
[tex]$$
(-2x) \cdot (-3) = 6x
$$[/tex]
3. Multiply the inner terms:
[tex]$$
(-9y^2) \cdot (-4x) = 36xy^2
$$[/tex]
4. Multiply the last terms:
[tex]$$
(-9y^2) \cdot (-3) = 27y^2
$$[/tex]
Now, add all the like terms together:
[tex]$$
8x^2 + 6x + 36xy^2 + 27y^2.
$$[/tex]
Thus, the product is:
[tex]$$
8x^2 + 6x + 36xy^2 + 27y^2.
$$[/tex]
[tex]$$
(-2x - 9y^2)(-4x - 3),
$$[/tex]
we multiply each term in the first parenthesis by each term in the second parenthesis.
1. Multiply the first terms:
[tex]$$
(-2x) \cdot (-4x) = 8x^2
$$[/tex]
2. Multiply the outer terms:
[tex]$$
(-2x) \cdot (-3) = 6x
$$[/tex]
3. Multiply the inner terms:
[tex]$$
(-9y^2) \cdot (-4x) = 36xy^2
$$[/tex]
4. Multiply the last terms:
[tex]$$
(-9y^2) \cdot (-3) = 27y^2
$$[/tex]
Now, add all the like terms together:
[tex]$$
8x^2 + 6x + 36xy^2 + 27y^2.
$$[/tex]
Thus, the product is:
[tex]$$
8x^2 + 6x + 36xy^2 + 27y^2.
$$[/tex]
