Answer :
To find the probability of getting at least 1 head on 4 successive tosses of a coin, we can use the concept of complementary probability.
Step-by-Step Explanation:
Understand the Problem:
- We want at least 1 head in 4 coin tosses.
- The complementary event is getting 0 heads in 4 coin tosses.
Calculate the Probability of the Complementary Event:
- Getting 0 heads means getting tails on all 4 tosses.
- The probability of getting a tail on one toss is [tex]\frac{1}{2}[/tex].
- Therefore, the probability of getting tails on 4 tosses is:
[tex]\left( \frac{1}{2} \right)^4 = \frac{1}{16}[/tex]
Calculate the Probability of Getting at Least 1 Head:
- The probability of at least 1 head is the complement of getting 0 heads:
[tex]1 - \frac{1}{16} = \frac{15}{16}[/tex]
- The probability of at least 1 head is the complement of getting 0 heads:
From the given multiple-choice options, the correct choice is:
- [tex]1 - \left( \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \right)[/tex]
This calculation demonstrates that the probability of getting at least 1 head in 4 successive tosses of a coin is [tex]\frac{15}{16}[/tex].