Answer :
To find the potential energy of a bicycle resting at the top of a hill, we can use the formula for gravitational potential energy:
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
For this problem:
- The mass [tex]\( m \)[/tex] is 25 kg (the mass of the bicycle),
- The height [tex]\( h \)[/tex] is 3 meters (the height of the hill).
Now, plug these values into the formula:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
When you multiply these together, you get:
[tex]\[ \text{PE} = 735 \, \text{Joules} \][/tex]
So, the potential energy of the bicycle at the top of the hill is 735 Joules.
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
For this problem:
- The mass [tex]\( m \)[/tex] is 25 kg (the mass of the bicycle),
- The height [tex]\( h \)[/tex] is 3 meters (the height of the hill).
Now, plug these values into the formula:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
When you multiply these together, you get:
[tex]\[ \text{PE} = 735 \, \text{Joules} \][/tex]
So, the potential energy of the bicycle at the top of the hill is 735 Joules.
