Answer :
To find the potential energy of a 25 kg bicycle at the top of a 3-meter high hill, we can use the formula for potential energy:
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
Where:
- [tex]\( m \)[/tex] is the mass, which is 25 kg in this case.
- [tex]\( g \)[/tex] is the acceleration due to gravity, approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
- [tex]\( h \)[/tex] is the height, which is 3 meters.
Now, let's calculate the potential energy:
1. Multiply the mass ([tex]\( m \)[/tex]) by the gravitational acceleration ([tex]\( g \)[/tex]):
[tex]\( 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 245 \, \text{N} \)[/tex] (Newtons).
2. Next, multiply the result by the height ([tex]\( h \)[/tex]):
[tex]\( 245 \, \text{N} \times 3 \, \text{m} = 735 \, \text{J} \)[/tex] (Joules).
So, the potential energy of the bicycle is [tex]\( 735 \, \text{J} \)[/tex]. Therefore, the correct answer is 735 J.
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
Where:
- [tex]\( m \)[/tex] is the mass, which is 25 kg in this case.
- [tex]\( g \)[/tex] is the acceleration due to gravity, approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
- [tex]\( h \)[/tex] is the height, which is 3 meters.
Now, let's calculate the potential energy:
1. Multiply the mass ([tex]\( m \)[/tex]) by the gravitational acceleration ([tex]\( g \)[/tex]):
[tex]\( 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 245 \, \text{N} \)[/tex] (Newtons).
2. Next, multiply the result by the height ([tex]\( h \)[/tex]):
[tex]\( 245 \, \text{N} \times 3 \, \text{m} = 735 \, \text{J} \)[/tex] (Joules).
So, the potential energy of the bicycle is [tex]\( 735 \, \text{J} \)[/tex]. Therefore, the correct answer is 735 J.
