Answer :
To find the potential energy of a 25 kg bicycle resting at the top of a 3 m high hill, we use the formula for potential energy:
[tex]\[ PE = m \cdot g \cdot h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object, which is 25 kg,
- [tex]\( g \)[/tex] is the acceleration due to gravity, typically [tex]\( 9.8 \, \text{m/s}^2 \)[/tex],
- [tex]\( h \)[/tex] is the height, which is 3 m.
Let's substitute the given values into the formula:
[tex]\[ PE = 25 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 \cdot 3 \, \text{m} \][/tex]
[tex]\[ PE = 25 \cdot 9.8 \cdot 3 \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
So, the potential energy of the bicycle is 735 Joules.
[tex]\[ PE = m \cdot g \cdot h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object, which is 25 kg,
- [tex]\( g \)[/tex] is the acceleration due to gravity, typically [tex]\( 9.8 \, \text{m/s}^2 \)[/tex],
- [tex]\( h \)[/tex] is the height, which is 3 m.
Let's substitute the given values into the formula:
[tex]\[ PE = 25 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 \cdot 3 \, \text{m} \][/tex]
[tex]\[ PE = 25 \cdot 9.8 \cdot 3 \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
So, the potential energy of the bicycle is 735 Joules.
