Answer :
To find the potential energy of a bicycle at the top of a hill, we can use the formula for gravitational potential energy:
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the bicycle,
- [tex]\( g \)[/tex] is the acceleration due to gravity,
- [tex]\( h \)[/tex] is the height of the hill.
In this problem:
- The mass [tex]\( m \)[/tex] of the bicycle is 25 kg.
- The acceleration due to gravity [tex]\( g \)[/tex] is typically 9.8 m/s².
- The height [tex]\( h \)[/tex] of the hill is 3 meters.
Let's plug these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the 25 kg bicycle resting at the top of a 3 m high hill is 735 Joules. The correct answer is 735 J.
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the bicycle,
- [tex]\( g \)[/tex] is the acceleration due to gravity,
- [tex]\( h \)[/tex] is the height of the hill.
In this problem:
- The mass [tex]\( m \)[/tex] of the bicycle is 25 kg.
- The acceleration due to gravity [tex]\( g \)[/tex] is typically 9.8 m/s².
- The height [tex]\( h \)[/tex] of the hill is 3 meters.
Let's plug these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the 25 kg bicycle resting at the top of a 3 m high hill is 735 Joules. The correct answer is 735 J.
