Answer :
To find the potential energy of the bicycle at the top of the hill, we can use the formula for gravitational potential energy:
[tex]\[ PE = m \cdot g \cdot h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the bicycle,
- [tex]\( g \)[/tex] is the acceleration due to gravity,
- [tex]\( h \)[/tex] is the height of the hill.
Let's substitute the given values into the formula:
- The mass ([tex]\( m \)[/tex]) of the bicycle is 25 kg.
- The acceleration due to gravity ([tex]\( g \)[/tex]) is approximately 9.8 m/s[tex]\(^2\)[/tex].
- The height ([tex]\( h \)[/tex]) of the hill is 3 meters.
Now, substituting these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
Calculating this gives:
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
So, the potential energy of the bicycle at the top of the hill is 735 Joules. Therefore, the correct answer is 735 J.
[tex]\[ PE = m \cdot g \cdot h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the bicycle,
- [tex]\( g \)[/tex] is the acceleration due to gravity,
- [tex]\( h \)[/tex] is the height of the hill.
Let's substitute the given values into the formula:
- The mass ([tex]\( m \)[/tex]) of the bicycle is 25 kg.
- The acceleration due to gravity ([tex]\( g \)[/tex]) is approximately 9.8 m/s[tex]\(^2\)[/tex].
- The height ([tex]\( h \)[/tex]) of the hill is 3 meters.
Now, substituting these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
Calculating this gives:
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
So, the potential energy of the bicycle at the top of the hill is 735 Joules. Therefore, the correct answer is 735 J.
