Answer :
To find the potential energy of a bicycle at the top of a hill, we can use the formula for gravitational potential energy, which is:
[tex]\[ \text{PE} = m \times g \times h \][/tex]
Here:
- [tex]\( m \)[/tex] is the mass of the bicycle, which is 25 kg.
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
- [tex]\( h \)[/tex] is the height of the hill, which is 3 m.
Step-by-Step Solution:
1. Identify the mass of the object, which is 25 kg in this case.
2. Determine the gravitational acceleration, which is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth's surface.
3. Measure or identify the height at which the object is located, which is 3 meters.
4. Use the potential energy formula:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
5. Calculate the product:
[tex]\( \text{PE} = 25 \times 9.8 \times 3 \)[/tex]
[tex]\( \text{PE} = 735 \, \text{J} \)[/tex]
Therefore, the potential energy of the 25 kg bicycle resting at the top of the 3-meter-high hill is 735 Joules.
[tex]\[ \text{PE} = m \times g \times h \][/tex]
Here:
- [tex]\( m \)[/tex] is the mass of the bicycle, which is 25 kg.
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
- [tex]\( h \)[/tex] is the height of the hill, which is 3 m.
Step-by-Step Solution:
1. Identify the mass of the object, which is 25 kg in this case.
2. Determine the gravitational acceleration, which is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth's surface.
3. Measure or identify the height at which the object is located, which is 3 meters.
4. Use the potential energy formula:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
5. Calculate the product:
[tex]\( \text{PE} = 25 \times 9.8 \times 3 \)[/tex]
[tex]\( \text{PE} = 735 \, \text{J} \)[/tex]
Therefore, the potential energy of the 25 kg bicycle resting at the top of the 3-meter-high hill is 735 Joules.
