Answer :
To find the potential energy of a bicycle at the top of a hill, we can use the formula:
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
Where:
- [tex]\( m = 25 \)[/tex] kg is the mass of the bicycle,
- [tex]\( g = 9.81 \)[/tex] m/s² is the acceleration due to gravity,
- [tex]\( h = 3 \)[/tex] m is the height of the hill.
Let's plug these values into the formula:
[tex]\[ \text{PE} = 25 \times 9.81 \times 3 \][/tex]
When you multiply these numbers, you get:
[tex]\[ \text{PE} = 735.75 \, \text{Joules} \][/tex]
Thus, the potential energy of the 25 kg bicycle resting at the top of a 3 m high hill is approximately 735.75 Joules.
Since we're choosing from the given options and if rounding is used, the closest choice is:
735 J
So, among the provided options, the correct answer is 735 J.
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
Where:
- [tex]\( m = 25 \)[/tex] kg is the mass of the bicycle,
- [tex]\( g = 9.81 \)[/tex] m/s² is the acceleration due to gravity,
- [tex]\( h = 3 \)[/tex] m is the height of the hill.
Let's plug these values into the formula:
[tex]\[ \text{PE} = 25 \times 9.81 \times 3 \][/tex]
When you multiply these numbers, you get:
[tex]\[ \text{PE} = 735.75 \, \text{Joules} \][/tex]
Thus, the potential energy of the 25 kg bicycle resting at the top of a 3 m high hill is approximately 735.75 Joules.
Since we're choosing from the given options and if rounding is used, the closest choice is:
735 J
So, among the provided options, the correct answer is 735 J.
