Answer :
Final answer:
The number of possible ways to get 3 successes out of 5 trials is 10. The correct option is B
Explanation:
To find the number of possible ways to get 3 successes out of 5 trials, we can use the combination formula. The formula for combination is:
C(n, k) = n! / (k!(n-k)!)
In this case, n = 5 (total number of trials) and k = 3 (number of successes).
Plugging in the values, we get:
C(5, 3) = 5! / (3!(5-3)!)
= 5! / (3!2!)
= (5 * 4 * 3 * 2 * 1) / ((3 * 2 * 1) * (2 * 1))
= 10
So, the number of possible ways to get 3 successes out of 5 trials is 10.
