High School

What is the new pressure of a 2.5-liter balloon if the original volume was 6.2 liters at a pressure of 3.3 atm?

A. 0.12 atm
B. 4.7 atm
C. 8.2 atm
D. 1.3 atm

Answer :

Using Boyle's Law, we calculated the new pressure of a balloon when its volume changes to be 8.2 atm

To find the new pressure of the balloon when the volume changes, we can use Boyle's Law. Boyle's Law states that the pressure of a gas times its volume is a constant when temperature and the amount of gas are held constant:

P1V1 = P2V2

Given:

  1. Initial volume (V1) = 6.2 liters
  2. Initial pressure (P1) = 3.3 atm
  3. Final volume (V2) = 2.5 liters

We need to find the final pressure (P2). Rearrange Boyle's Law to solve for P2:

P2 = (P1V1) / V2

Substitute the known values:

P2 = (3.3 atm * 6.2 liters) / 2.5 liters ≈ 8.2 atm

Therefore, the new pressure of the balloon is 8.2 atm.

Answer:

P₂ = 8.2 atm

Explanation:

Given data:

Final pressure = ?

Final volume = 2.5 L

Initial volume = 6.2 L

Initial pressure = 3.3 atm

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

3.3 atm × 6.2 L = P₂ × 2.5 L

P₂ = 20.46 atm. L/2.5 L

P₂ = 8.2 atm