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------------------------------------------------ What is the mole fraction of [tex]CO_2[/tex] in this mixture consisting of 17 g of [tex]CO_2[/tex] and 39.1 g of [tex]O_2[/tex]?

Answer :

Final answer:

The mole fraction of CO₂ in the mixture of 17 g of CO₂ and 39.1 g of O₂ is 0.24.

Explanation:

To find the mole fraction of CO₂ in the mixture, we first need to calculate the number of moles of CO₂ and O₂. The molar mass of CO₂ is 44 g/mol, so 17 g of CO₂ is equal to 17/44 = 0.386 moles. The molar mass of O₂ is 32 g/mol, so 39.1 g of O₂ is equal to 39.1/32 = 1.22 moles. The mole fraction of CO₂ can be calculated by dividing the moles of CO₂ by the total moles of both gases:



Mole fraction of CO₂ = (0.386 moles of CO₂) / (0.386 moles of CO₂ + 1.22 moles of O₂) = 0.24

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