High School

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ What is the molarity of NaCl in a solution when 97.4 g of NaCl (formula mass = 58.4 g/mol) are used to make a final solution of 897 mL? Enter the answer to 3 decimal places.

Answer :

The molarity of NaCl in the solution is 1.997 M.

First, we need to calculate the number of moles of NaCl used in the solution:

moles of NaCl = mass of NaCl / formula mass of NaCl
moles of NaCl = 97.4 g / 58.4 g/mol
moles of NaCl = 1.666 moles

Next, we need to calculate the volume of the solution in liters:
volume of solution = 897 ml ÷ 1000 ml/L
volume of solution = 0.897 L

Finally, we can calculate the molarity using the formula:
molarity = moles of solute / volume of solution
molarity = 1.666 moles / 0.897 L
molarity = 1.997 M


NaCl in the solution therefore has a molarity of 1.997 M.

To learn more about molarity visit:

https://brainly.com/question/30404105

#SPJ11

Other Questions