High School

What is the molarity of an HCl solution if 35.5 mL of 0.10 M NaOH are needed to neutralize 25.0 mL of the sample?

Answer :

Final answer:

The molarity of the HCl solution is 0.142 M.

Explanation:

To find the molarity of the HCl solution, we can use the equation:

M1V1 = M2V2

Where M1 is the molarity of NaOH, V1 is the volume of NaOH used, M2 is the molarity of HCl, and V2 is the volume of HCl used.

In this problem, M1 = 0.10 M, V1 = 35.5 mL (convert to L), V2 = 25.0 mL (convert to L). Solving for M2, we get:

M2 = (M1 * V1) / V2

Substituting the given values gives:

M2 = (0.10 M * 0.0355 L) / 0.0250 L = 0.142 M

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