Answer :
The molarity of the solution prepared by diluting 35.8 mL of 6.5 M HCl to 250.0 mL is 0.93 M. The correct option is b. 0.93 M .
The molarity of a solution after dilution can be determined using the equation M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial concentrated solution, and M2 and V2 are the molarity and volume of the diluted solution.
In the given problem, we have:
Initial molarity (M1) = 6.5 M
Initial volume (V1) = 35.8 mL
Final volume (V2) = 250.0 mL
Using the equation M1V1 = M2V2, we calculate the final molarity (M2) as follows:
M2 = (M1V1) / V2 = (6.5 M * 35.8 mL) / 250.0 mL = 0.93 M
The molarity of the diluted HCl solution is therefore 0.93 M. The correct option is b. 0.93 M .
