Answer :
The molarity or molar concentration is calculted by dividin the number of moles of solute, n, by the total volume of the solution, V, and normally presented in mol/L.
So:
[tex]C=\frac{n}{V}[/tex]We know that the number of moles of AgNO₃ is 98.1 mol and the volume is 0.250 L, so the molarity, C, will be:
[tex]C=\frac{n}{V}=\frac{98.1mol}{0.250L}=392.4mol\/L\approx392mol\/L[/tex]So, the molarity will be approximately 392 mol/L.
