Answer :
Final answer:
The mass of Na2SO4 produced when 67 g of sulfuric acid is mixed with 33.7 g of sodium hydroxide is 104.5 g.
(c) 104.5 g
Explanation:
To solve this problem, we need to calculate the moles of sulfuric acid (H2SO4) and sodium hydroxide (NaOH) using their respective masses and molar masses. Then, we can use the balanced chemical equation to determine the molar ratio between H2SO4 and Na2SO4. Finally, we can calculate the mass of Na2SO4 using the mole ratio and the molar mass of Na2SO4.
Step 1: Calculate the moles of H2SO4 and NaOH
Moles of H2SO4 = mass of H2SO4 / molar mass of H2SO4
Moles of NaOH = mass of NaOH / molar mass of NaOH
Step 2: Determine the mole ratio between H2SO4 and Na2SO4 from the balanced equation
The balanced equation is 2NaOH + H2SO4 → Na2SO4 + 2H2O
The mole ratio between H2SO4 and Na2SO4 is 1:1
Step 3: Calculate the mass of Na2SO4
Mass of Na2SO4 = moles of Na2SO4 * molar mass of Na2SO4
Using this method with the given masses, we find that the mass of Na2SO4 produced is 104.5 g.
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