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------------------------------------------------ What is the magnitude of the magnetic field inside a 372-turn toroid carrying a current of 1.69 A, at a radius of 4.60 m?

The magnitude of the magnetic field inside the toroid is 0.021 Tesla. Magnitude of the magnetic field inside a toroid can be calculated using the formula: B = (μ₀ * N * I) / (2π * r)

- B represents the magnitude of the magnetic field
- μ₀ is the permeability of free space, which is a constant equal to 4π * 10⁻⁷ T*m/A
- N is the number of turns in the toroid (372 turns in this case)
- I is the current flowing through the toroid (1.69 A in this case)
- r is the radius of the toroid (4.60 m in this case)

Substituting the given values into the formula:

B = (4π * 10⁻⁷ T*m/A * 372 turns * 1.69 A) / (2π * 4.60 m)

Simplifying the expression:

B = (4 * 3.14 * 10⁻⁷ * 372 * 1.69) / (2 * 4.60)

B = 0.021 T

Therefore, the magnitude of the magnetic field inside the toroid is 0.021 Tesla.

To know more about magnetic field, refer

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