High School

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ What is the magnitude of the magnetic field inside a 372-turn toroid carrying a current of 1.69 A, at a radius of 4.60 m?

Answer :

The magnitude of the magnetic field inside the toroid is 0.021 Tesla. Magnitude of the magnetic field inside a toroid can be calculated using the formula: B = (μ₀ * N * I) / (2π * r)


- B represents the magnitude of the magnetic field
- μ₀ is the permeability of free space, which is a constant equal to 4π * 10⁻⁷ T*m/A
- N is the number of turns in the toroid (372 turns in this case)
- I is the current flowing through the toroid (1.69 A in this case)
- r is the radius of the toroid (4.60 m in this case)

Substituting the given values into the formula:

B = (4π * 10⁻⁷ T*m/A * 372 turns * 1.69 A) / (2π * 4.60 m)

Simplifying the expression:

B = (4 * 3.14 * 10⁻⁷ * 372 * 1.69) / (2 * 4.60)

B = 0.021 T

Therefore, the magnitude of the magnetic field inside the toroid is 0.021 Tesla.

To know more about magnetic field, refer

https://brainly.com/question/14411049

#SPJ11