High School

What is the magnification of a curved mirror if a 10.0 cm tall object is placed 8.00 cm from the mirror and produces an image 4.00 cm in front of the mirror?

A. 2.00
B. -2.00
C. 0.500
D. -0.500

Answer :

The magnification of the curved mirror in this scenario is -0.500.

The magnification of a mirror is defined as the ratio of the height of the image to the height of the object. It can be calculated using the formula:

magnification = height of image / height of object.

In this case, the height of the object is given as 10.0 cm, and the height of the image is not explicitly given. However, we can use the information about the object's distance from the mirror and the distance of the image from the mirror to determine the height of the image using the mirror equation.

The mirror equation is given by:

1/f = 1/do + 1/di,

where f is the focal length of the mirror, do is the object distance, and di is the image distance. Since the problem statement mentions that the mirror is curved, we can assume it is a concave or convex mirror with a positive focal length.

In this case, the object distance (do) is given as 8.00 cm, and the image distance (di) is given as -4.00 cm (since it is in front of the mirror). The negative sign indicates that the image is virtual and upright.

Using the mirror equation, we can solve for the focal length (f):

1/f = 1/8.00 + 1/-4.00.

Simplifying the equation:

1/f = -1/8.00.

Multiplying both sides by 8.00:

1/f = -1/8.00.

Therefore, the magnification is -0.500.

The negative magnification indicates that the image formed by the mirror is inverted compared to the object. Additionally, the magnification value of -0.500 means that the image is half the height of the object.

To learn more about magnification, click here: brainly.com/question/3480304

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