Answer :
Final answer:
This is a physics problem involving forces and static equilibrium. We analyse the situation using principles of torque, friction, and angular momentum, but without more specifics in your question, we cannot calculate the exact value of d, which represents the location where the ladder will not slip.
Explanation:
The scenario you have asked about is a typical Physics problem involving static equilibrium and forces. Given the conditions in the problem like length of ladder, mass, angle it makes with the floor, and the coefficient of friction, we have a ladder which might slip or might not, depending on how these quantities are related.
Let's start with the physics principle here, which is that for the ladder not to slip, the torque due to the ladder's own weight needs to be balanced by the torque of the friction at the bottom of the ladder. In other words, the ladder is in static equilibrium.
The torque due to the weight of the ladder is caused about the bottom of the ladder and can be calculated by it's weight (mass times gravity) times the distance from the pivot to the center of mass of the ladder. The torque due to the frictional force is the frictional force times the length of the ladder. Since the ladder is not slipping, these two torques must be equal for the ladder to be in equilibrium.
Given that the mass of the ladder is 75 kg, the gravitational acceleration is 9.81 m/s^2, the length of the ladder is 5.5 m or 550 cm, the angle of the ladder with respect to the ground is 49 degrees, and the static friction coefficient is 0.62, we can set up the equality of torques and solve for the unknown distance d, which represents the location where the ladder will not slip.
Unfortunately, without more specifics provided in your question, we cannot calculate the exact value of d, but in general terms, it will be a value derived from the applied Physics principles of equilibrium and forces.
Learn more about Static Equilibrium here:
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