High School

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ What is the kilowatt output of an electric heater that has an ampere draw of [tex]50 \text{A}[/tex] and a voltage source of [tex]208 \text{V}[/tex]?

Calculate [tex]208 \times 50[/tex] and express the answer in kilowatts, rounded to the thousandths place.

Answer :

Final answer:

The kilowatt output of an electric heater with an ampere draw of 50A and a voltage source of 208V is 10.4 kilowatts.

Explanation:

The power output of an electrical device such as an electric heater can be calculated using the formula P=IV, where P is the power in watts, I is the current in amperes and V is the voltage in volts. In this case, the current, I is 50A and the voltage, V is 208V. So, the power P in watt is calculated by multiplying the current and the voltage which gives P = IV = 50A x 208V = 10400W.

To convert this power to kilowatts, we will divide the power in watts by 1000. This gives us 10.4 kilowatts. Therefore, the power output of the electric heater is 10.4 kilowatts.

Learn more about Power Output here:

https://brainly.com/question/38325928

#SPJ11