Answer :
The heat change associated with 37.19 g of liquid water at 5.00 °C changing to solid water at -5.00 °C is approximately 12.4007 kJ.
The heat change associated with a phase change can be calculated using the heat of fusion, which is the amount of heat required to change a given mass of a substance from a solid to a liquid, or vice versa. The heat of fusion for water is approximately 333 J/g.
The heat change associated with 37.19 g of liquid water at 5.00 °C changing to solid water at -5.00 °C can be calculated as:
q = m * ΔHfusion
where m is the mass of the water and ΔHfusion is the heat of fusion. In this case, m = 37.19 g and ΔHfusion = 333 J/g, so:
q = 37.19 g * 333 J/g = 12400.07 J
To convert the heat change from joules to kilojoules, divide by 1000:
q = 12400.07 J / 1000 = 12.4007 kJ
So the heat change associated with 37.19 g of liquid water at 5.00 °C changing to solid water at -5.00 °C is approximately 12.4007 kJ.
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