High School

What is the cube root of [tex]$27x^{18}$[/tex]?

A. [tex]$3x^6$[/tex]
B. [tex][tex]$3x^9$[/tex][/tex]
C. [tex]$9x^6$[/tex]
D. [tex]$9x^9$[/tex]

Answer :

Sure! Let's solve the problem step by step to find the cube root of [tex]\(27x^{18}\)[/tex].

1. Find the cube root of 27:

- The number 27 is a perfect cube, as [tex]\(27 = 3 \times 3 \times 3 = 3^3\)[/tex].
- Therefore, the cube root of 27 is 3.

2. Find the cube root of [tex]\(x^{18}\)[/tex]:

- When finding the cube root of a variable expression like [tex]\(x^{18}\)[/tex], we divide the exponent by 3.
- So, the cube root of [tex]\(x^{18}\)[/tex] is [tex]\(x^{18/3} = x^6\)[/tex].

3. Combine the results:

- We multiply the cube root of the numerical part by the cube root of the variable expression.
- This gives us [tex]\(3 \times x^6\)[/tex].

Therefore, the cube root of [tex]\(27x^{18}\)[/tex] is [tex]\(3x^6\)[/tex].

The correct choice is [tex]\(3x^6\)[/tex].