Water was taken in four beakers labeled as I to IV. To these beakers, the following substances were added:

- Beaker (I): Common salt
- Beaker (II): Alum
- Beaker (III): Potassium nitrate
- Beaker (IV): A few drops of barium chloride and a few drops of dilute sulfuric acid

After some time, the contents of the beakers were filtered. The contents of which beaker will leave residue on the filter paper?

a. Beaker (I)
b. Beaker (II)
c. Beaker (III)
d. Beaker (IV)

The contents of beaker IV, with barium chloride and dilute sulphuric acid added to it, would leave a residue upon filtration due to the formation of insoluble barium sulfate.

Explanation:

The question asks which of the four beakers, labeled I to IV, with specific substances added to them, will leave residue on the filter paper after filtration.

Common salt (in beaker I), alum (in beaker II), and Potassium nitrate (beaker III) are all soluble in water, meaning they will dissolve and not leave behind a residue. However, when barium chloride reacts with dilute sulphuric acid (as in Beaker IV), it forms barium sulfate which is insoluble in water, and will therefore remain as a residue on the filter paper after the filtration process.

So, the contents of beaker IV will leave a residue on the filter paper.

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