College

Water flows uniformly at a depth of 1.2 m (4 ft) in a rectangular canal 3 m (10 ft) wide, laid on a slope of 1 m per 1,000 m (1 ft per 1,000 ft). What is the mean shear stress on the sides and bottom of the canal?

Answer :

The mean shear stress on the sides and bottom of the canal can be calculated using the concept of fluid mechanics and the principles of open channel flow. In open channel flow, the shear stress is caused by the friction between the flowing water and the boundary surfaces of the channel.

The mean shear stress on the sides and bottom of the canal can be determined using Manning's equation, which relates the shear stress to the hydraulic radius and the channel slope. Manning's equation is as follows:

width (b) = 3m

depth (9) = 1.2m

slope =1.2m

1000

mean sheep stress = 3m

=9870

So

=

3. R. So

1000

A = bxy = 1.2x3

P = b+2y

R = A Р

1.2x3

3+2(1.2)

8.R.So

Zmean

=

=

=

= 0.67

(1/0)

1000

(9870) (0.67) (

=

6.54 KN/m2

3+ 2(1.2)

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