Using the superposition theorem, what is the portion of the current through the 6 Ω resistor caused by the 8 V battery?

Using the superposition theorem and Ohm's Law, the portion of the current through the 6 Ω resistor caused by the 8 V battery can be calculated as I = 8 V / 6 Ω, resulting in a current of 1.33 A.

Explanation:

To determine the portion of the current through the 6 Ω resistor caused by the 8 V battery using the superposition theorem, we first isolate the 8 V battery, treating other power sources as open circuits. Hence, we only consider the 8 V battery and its effect on the circuit.

First, apply Ohm's Law, V = IR

where V is voltage, I is current, and R is resistance. In your case, the resistance (R) is 6 Ω and the voltage (V) is the 8 V provided by the battery.

To find current (I), we rearrange Ohm's Law to derive I = V/R.

For the circuit, this gives:

I = 8 V / 6 Ω

I = 1.33 A.

This is the portion of the current through the 6 Ω resistor caused by the 8 V battery in accordance with the superposition theorem.

Learn more about Superposition Theorem here:

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