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------------------------------------------------ Using the equation [tex]y = 20000(0.95)^x[/tex], predict the purchasing power of [tex]\$20,000[/tex] ten years later.

A. [tex]\$10,255[/tex]
B. [tex]\$11,975[/tex]
C. [tex]\$12,635[/tex]
D. [tex]\$14,560[/tex]

Answer :

- Substitute $x = 10$ into the equation $y = 20000(0.95)^x$.
- Calculate $y = 20000(0.95)^{10}$, which is approximately $11974.74.
- Compare the result with the given options.
- The closest option is $\boxed{{\$11,975}}$.

### Explanation
1. Understanding the Problem
We are given the equation $y = 20000(0.95)^x$, which models the purchasing power of an initial amount of $20,000 after $x$ years. We want to find the purchasing power 10 years later, so we need to substitute $x = 10$ into the equation.

2. Substituting the Value of x
Substitute $x = 10$ into the equation: $y = 20000(0.95)^{10}$.

3. Calculating the Purchasing Power
Calculate the value of $y$: $y = 20000 \times (0.95)^{10}$. The result of this calculation is approximately $11974.74.

4. Comparing with the Options
Now we compare the calculated value with the given options:
$10,255
$11,975
$12,635
$14,560
The closest value to our calculated result ($11974.74) is $11,975.

5. Final Answer
Therefore, the predicted purchasing power of $20,000 ten years later is approximately $\boxed{{\$11,975}}$.

### Examples
Understanding the depreciation of assets or the erosion of purchasing power due to inflation is crucial in financial planning. For instance, if you have $20,000 today, this equation helps you estimate its value in 10 years, considering a 5% annual decrease in purchasing power. This concept is useful in making informed decisions about investments, savings, and long-term financial goals. It allows you to account for the time value of money and plan accordingly to maintain or grow your wealth effectively.