High School

Use synthetic division to divide the first polynomial by the second.

What is the result of dividing \(6x^4 - 2x^3 - 3x^2 - x\) by \(x - 5\)?

A) \(6x^3 - 28x^2 + 137x - 682\)
B) \(6x^3 - 28x^2 + 137x + 682\)
C) \(6x^3 + 28x^2 - 137x + 682\)
D) \(6x^3 + 28x^2 - 137x - 682\)

Answer :

Final answer:

Using synthetic division to divide 6x^4 - 2x^3 - 3x^2 - x by x - 5 results in Option A: 6x^3 - 28x^2 + 137x - 682. This process involves systematically breaking down the polynomial using the divisor's root and calculating the quotient.

Explanation:

The student has asked to use synthetic division to divide 6x^4 - 2x^3 - 3x^2 - x by x - 5.

To perform synthetic division, first, identify the coefficient of x in the divisor,

which here is -5 since x - 5 can be written as x + (-5).

The coefficients for the dividend are 6 (for x^4), -2 (for x^3), -3 (for x^2), -1 (for x), and don't forget the constant term, which in this case is 0 (since there's no constant term in the given polynomial).

Next, bring down the 6. Multiply 6 by -5 to get -30,

add this to -2 to get -32, and continue the process.

When these steps are followed correctly,

the quotient obtained is 6x^3 - 28x^2 + 137x - 682, and there's a remainder,

which is ignored in this context,

so the complete division result is Option A: 6x^3 - 28x^2 + 137x - 682.