Answer :
The force of friction acting on Tyler as he slides across the kitchen floor with a mass of 67 kg and a coefficient of kinetic friction of 0.3 is approximately 197 N, which matches option A.
To calculate the force of friction acting on Tyler as he slides across the floor, we use the formula:
Friction force (f) = Coefficient of kinetic friction (μk) *Normal force (N)
The normal force for an object on a flat surface is equal to the object's weight, which is the mass times the acceleration due to gravity. Here, gravity (g) is typically 9.8 m/s2.
N = mass (m) * gravity (g) = 67 kg * 9.8 m/s2 = 656.6 N (rounded to 657 N)
Now we multiply the normal force by the coefficient of kinetic friction:
f = 0.3 * 656.6 N = 196.98 N (rounded to 197 N)
Therefore, the friction force acting on Tyler is about 197 N, which correlates to option A.
