Answer :
When the two strings are played together, we will hear a sound that fluctuates between 660 Hz and 662 Hz at a rate of 2 times per second.
How to solve
The fundamental frequency of a string is given by:
f = (1/2L) * sqrt(T/mu)
where L is the length of the string, T is the tension, and mu is the linear mass density.
In this case, the two strings have the same linear mass density and length, so the only difference is the tension. When the tension is increased to 102 N, the frequency of the string becomes:
f = (1/2L) * sqrt(102/0.0014) = 662 Hz
The beat frequency is the difference between the frequencies of the two strings, which is 662 Hz - 660 Hz = 2 Hz.
In other words, when the two strings are played together, we will hear a sound that fluctuates between 660 Hz and 662 Hz at a rate of 2 times per second.
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