Answer :
To find the resistor with the largest resistance, let's use Ohm's law formula V = IR. where V is the voltage, I is the current, and R is the resistance. The resistor A has the largest resistance. The correct answer is resistor A.
We are given that two resistors, A and B, are connected in series to a 9 V battery. Also, the first resistor, A, has a voltage of 6 V across it. This means that the voltage across resistor B is 9 V - 6 V = 3 V.
Now, let's find the resistance of resistor A using Ohm's law:
R = V / I
where V = 6 V and I is the same as the current flowing through resistor B since they are connected in series. Let's assume the current is I.
Therefore,
Ra = 6 V / I
Now, let's find the resistance of resistor B using Ohm's law:
R = V / I
where V = 3 V and I is the current flowing through both resistors in series.
Therefore,
Rb = 3 V / I
We are to find which resistor has the largest resistance.
This means we should compare Ra and Rb.
Ra = 6 V / I
Rb = 3 V / I
To compare the two resistances, we can simplify them as follows:
Ra = 6 / I
Rb = 3 / I
We can see that Ra is twice the value of Rb.
Therefore, resistor A has the largest resistance. Answer: Resistor A
Here you can learn more about Ohm's law
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