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------------------------------------------------ Two resistors, A and B, are connected in series to a 9 V battery. The first resistor, Resistor A, has a voltage of 6 V across it. Which resistor has the largest resistance?

Answer :

To find the resistor with the largest resistance, let's use Ohm's law formula V = IR. where V is the voltage, I is the current, and R is the resistance. The resistor A has the largest resistance. The correct answer is resistor A.

We are given that two resistors, A and B, are connected in series to a 9 V battery. Also, the first resistor, A, has a voltage of 6 V across it. This means that the voltage across resistor B is 9 V - 6 V = 3 V.

Now, let's find the resistance of resistor A using Ohm's law:

R = V / I

where V = 6 V and I is the same as the current flowing through resistor B since they are connected in series. Let's assume the current is I.

Therefore,

Ra = 6 V / I

Now, let's find the resistance of resistor B using Ohm's law:

R = V / I

where V = 3 V and I is the current flowing through both resistors in series.

Therefore,

Rb = 3 V / I

We are to find which resistor has the largest resistance.

This means we should compare Ra and Rb.

Ra = 6 V / I

Rb = 3 V / I

To compare the two resistances, we can simplify them as follows:

Ra = 6 / I

Rb = 3 / I

We can see that Ra is twice the value of Rb.

Therefore, resistor A has the largest resistance. Answer: Resistor A

Here you can learn more about Ohm's law

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