Answer :
To determine the size of the class 5.8 coarse-thread metric bolt required, we need to consider the static tensile load and the safety factor.
1. Calculate the maximum tensile load the bolt should be able to handle:
Given that each bolt carries a static tensile load of 3700 N, and the safety factor is 4, we need to multiply the load by the safety factor:
Maximum tensile load = 3700 N * 4 = 14800 N
2. Refer to a metric bolt size chart to find a suitable bolt that can withstand the maximum tensile load.
Class 5.8 refers to the tensile strength of the bolt. In this case, it means the bolt can withstand a tensile strength of up to 580 N/mm².
Let's assume the diameter of the bolt is "d" in millimeters (mm). The tensile load can be calculated using the following formula:
Tensile load = (π * d² * 0.7854) * tensile strength
Rearranging the formula, we can solve for the bolt diameter (d):
d = sqrt((Tensile load) / (π * 0.7854 * tensile strength))
3. Substitute the values into the formula:
d = sqrt((14800 N) / (π * 0.7854 * 580 N/mm²))
Calculating this gives us:
d ≈ 6.65 mm
Since the diameter of the bolt needs to be an integer, we can round this value to the nearest whole number:
d ≈ 7 mm
Therefore, a class 5.8 coarse-thread metric bolt with a diameter of 7 mm is required to hold the two parts of the machine together.
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