High School

Two objects, each with a mass of [tex]1.00 \times 10^3 \, \text{kg}[/tex], are positioned 4.00 m apart. If the center of one mass is at the origin of the x-axis, and the other is located at 4.00 m along the x-axis, what is the magnitude of the gravitational field due to both masses at a point 8.00 m along the positive x-axis?

Each gravitational field acts independently. Use a free body diagram and add the vectors.

Answer :

The magnitude of the combined gravitational field at the point (8.00 m along the positive x-axis) is 4.67 × 10⁻⁷ N/kg .

To find the combined gravitational field at a point due to two masses, we can treat each mass individually and then add the vector contributions from each. Here's how we can solve this problem:

Step 1: Define the masses and positions:

Mass of each object (m1 and m2): 1.00 × 10³ kg

Position of the first mass (x1): 0.00 m (origin)

Position of the second mass (x2): 4.00 m

Point of interest (x3): 8.00 m

Step 2: Calculate the gravitational constant (G):

G = 6.6743 × 10⁻¹¹ m³ kg⁻¹ s⁻²

Step 3: Calculate the vectors from each mass to the point of interest:

Vector from the first mass (r1): [x3 - x1, 0, 0] = [8.00 m, 0, 0]

Vector from the second mass (r2): [x3 - x2, 0, 0] = [4.00 m, 0, 0]

Step 4: Calculate the magnitudes of the vectors:

r1_mag = ||r1|| = √(8.00² + 0² + 0²) = 8.00 m

r2_mag = ||r2|| = √(4.00² + 0² + 0²) = 4.00 m

Step 5: Calculate the gravitational force due to each mass:

Force due to the first mass (F1):

F1 = G * m1 * m2 / (r1_mag³ * r1)

= (6.6743 × 10⁻¹¹ m³ kg⁻¹ s⁻²) * (1.00 × 10³ kg) * (1.00 × 10³ kg) / (8.00³ m³ * [8.00, 0, 0])

= [−3.33714844 × 10⁻⁷ N, 0, 0]

Force due to the second mass (F2):

F2 = G * m2 * m2 / (r2_mag³ * r2)

= (6.6743 × 10⁻¹¹ m³ kg⁻¹ s⁻²) * (1.00 × 10³ kg) * (1.00 × 10³ kg) / (4.00³ m³ * [4.00, 0, 0])

= [−1.33485937 × 10⁻⁷ N, 0, 0]

Step 6: Combine the forces (vector addition):

Gravitational field at the point (F_total): F_total = F1 + F2 = [-3.33714844 × 10⁻⁷ N - 1.33485937 × 10⁻⁷ N, 0, 0] = [-4.67200781 × 10⁻⁷ N, 0, 0]

Step 7: Calculate the magnitude of the combined gravitational field

Magnitude of F_total: ||F_total|| = √((-4.67200781 × 10⁻⁷ N)² + 0² + 0²) = 4.67200781 × 10⁻⁷ N

Therefore, the magnitude of the combined gravitational field at the point (8.00 m along the positive x-axis) is 4.67 × 10⁻⁷ N/kg .

Final answer:

Explanation on how to calculate the combined gravitational field at a specific point due to two masses.

Explanation:

Gravitational field is a vector quantity that describes the force experienced by a unit mass at a certain point in space due to a gravitational source. In this scenario, to find the combined gravitational field at 8.00 m along the positive x-axis, we first calculate the individual gravitational fields of the two masses at that point and then add them vectorially to get the total field.

To solve the problem:

  1. Calculate the gravitational field at 8.00 m due to the first mass.
  2. Calculate the gravitational field at 8.00 m due to the second mass.
  3. Add the two vectors using vector addition to obtain the total gravitational field at 8.00 m.