Answer :
When two friends push a stalled 1330kg car with 187N force then it takes approximately 10.47 seconds for the two friends to move the car 5.00 meters.
To calculate the time it takes to move the car, we can use Newton's second law of motion, which states that force is equal to mass times acceleration (F = m * a).
In this case, the force applied by the two friends is 187 N, and the mass of the car is 1330 kg. We need to find the acceleration of the car.
Using Newton's second law, we can rearrange the equation to solve for acceleration: a = F / m.
Substituting the given values, we get a = 187 N / 1330 kg = 0.14 m/s².
Now, we can use the kinematic equation s = ut + 0.5at² to find the time it takes for the car to move 5.00 m.
In this equation, s represents the displacement, u represents the initial velocity (which is assumed to be zero since the car is initially stalled), a represents the acceleration, and t represents the time.
Rearranging the equation, we have t = sqrt(2s / a).
Substituting the values, we get t = sqrt(2 * 5.00 m / 0.14 m/s²) ≈ 10.47 s.
Therefore, it takes approximately 10.47 seconds for the two friends to move the car 5.00 meters.
Learn more about Newton's second law:
https://brainly.com/question/25545050
#SPJ11
