Answer :
Final answer:
The velocity of the two football players just after impact, when they cling together, is approximately 0.86 m/s in the direction of the first player.
Explanation:
The subject of your question pertains to the physics concept of conservation of momentum, specifically during a collision. The equation we would use here is m1v1 + m2v2 = (m1 + m2)vf, where m is mass, v is velocity prior to the collision and vf is the final velocity after the collision. Plugging in the given values: (102 kg * 6.10 m/s) + (112 kg * -3.40 m/s) = (102 kg + 112 kg) * vf. After computation, we find that vf, or the velocity after the collision when they cling together, is approximately 0.86 m/s (positive meaning in the same direction as the velocity of the first player), given that all values are in SI units.
Learn more about Conservation of Momentum here:
https://brainly.com/question/32309314
#SPJ11
