to see if the elevator at the tempe campus has a different acceleration, we take a scale to the elevator in the physical sciences building. the person who goes has a mass of 114 kg. as the elevator begins to go up, the scale reads 1482 n. what is the initial acceleration of the elevator?

The initial acceleration of the elevator at the Tempe campus, as the elevator starts to move upward and according to the given scale reading and person's weight, is approximately 3.2 m/s².

Explanation:

To find the initial acceleration of the elevator, we can use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration (Fnet = ma). In this case, the scale reading is 1482 N, which is actually the net force acting on the person as the elevator starts to move up.

The person's gravitational force (Fg) or weight can be found using the formula Fg = mg, where 'm' is the mass and 'g' is the acceleration due to gravity (9.8 m/s²). So, the person’s weight is 114 kg * 9.8 m/s² = 1117.2 N.

As the person is in the elevator moving upward, the net force is the difference between the scale force (Fs) and the gravitational force (Fg), so we can write the equation as: Fs - Fg = ma.

Substituting values, we get: 1482 N - 1117.2 N = 114 kg * a . So, the initial acceleration 'a' of the elevator is approximately 3.2 m/s².

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